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Pochodna funkcji -4x^2+8x+1

$f\left(x\right) =$	$-4{x}^{2}+8x+1$
$\dfrac{\mathrm{d}\left(f\left(x\right)\right)}{\mathrm{d}x} =$	$\class{steps-node}{\cssId{steps-node-1}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(-4{x}^{2}+8x+1\right)}}$ $=\class{steps-node}{\cssId{steps-node-2}{8-4{\cdot}\class{steps-node}{\cssId{steps-node-3}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left({x}^{2}\right)}}}}$ $=8-4{\cdot}\class{steps-node}{\cssId{steps-node-4}{2}}\class{steps-node}{\cssId{steps-node-5}{x}}$ $=8-8x$

$f\left(x\right) =$

$-4{x}^{2}+8x+1$

$\dfrac{\mathrm{d}\left(f\left(x\right)\right)}{\mathrm{d}x} =$

$\class{steps-node}{\cssId{steps-node-1}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(-4{x}^{2}+8x+1\right)}}$

$=\class{steps-node}{\cssId{steps-node-2}{8-4{\cdot}\class{steps-node}{\cssId{steps-node-3}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left({x}^{2}\right)}}}}$

$=8-4{\cdot}\class{steps-node}{\cssId{steps-node-4}{2}}\class{steps-node}{\cssId{steps-node-5}{x}}$

$=8-8x$